Scenario: You have created a popover view using iOS storyboard. The popover view is triggered by the clicking of a 'button' on the UINavigationBar or UIToolbar. Once the popover view appears, you can click outside of the popover view to dismiss it. But if you click the 'button' again, another popover view appear on top of the existing one. To dismiss the popover views, you need to click outside the popover view twice to dismiss it. (Indeed, more popover view will appear if you click the 'button' again.) Not a nice behavior to have.
Disable the 'button'.
You need to disable the 'button' when the segue is triggered and re-enable it when the user's click outside the popover view.
1. Create two accessors using the usual @property & @synthesize approach.
Under @interface,
@property (strong, nonatomic) IBOutlet UIBarButtonItem *btnSettings;
@property (strong, nonatomic) UIStoryboardPopoverSegue* popSegue;
Under @implementation,
@synthesize btnSettings = _btnSettings;
@synthesize popSegue = _popSegue;
(Remember to link up the actual button to the IBOutlet in Interface Builder.)
2. Make the viewcontroller confirms to the UIPopoverControllerDelegate protocol
eg. @interface ViewController : UIViewController <UIPopoverControllerDelegate>
3. Inside the method (void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender
if ([segue.identifier isEqualToString:@"NAME_OF_YOUR_SEGUE"]) {
//- for this purpose alone, you don't really need a popSegue property, but having a reference
//- to the popover segue is useful
self.popSegue = (UIStoryboardPopoverSegue *)segue;
//- this gets the reference to the actual UIPopoverController which you need to set the delegate
UIPopoverController *pc = [_popSegue popoverController];
//- setting the delegate to self
//- this is important, otherwise the method under (4) won't be called and your button will remain disabled!
pc.delegate = self;
//- disable the button to prevent creating another popover
[_btnSettings setEnabled:NO];
}
4. Implement the following method in the UIPopoverControllerDelegate protocol,
- (void)popoverControllerDidDismissPopover:(UIPopoverController *)popoverController
{
//- renable the setting button
[_btnSettings setEnabled:YES];
}
As the name suggests, this method gets call whenever the user click outsdie the popover view.
Disable the 'button'.
You need to disable the 'button' when the segue is triggered and re-enable it when the user's click outside the popover view.
1. Create two accessors using the usual @property & @synthesize approach.
Under @interface,
@property (strong, nonatomic) IBOutlet UIBarButtonItem *btnSettings;
@property (strong, nonatomic) UIStoryboardPopoverSegue* popSegue;
Under @implementation,
@synthesize btnSettings = _btnSettings;
@synthesize popSegue = _popSegue;
(Remember to link up the actual button to the IBOutlet in Interface Builder.)
2. Make the viewcontroller confirms to the UIPopoverControllerDelegate protocol
eg. @interface ViewController : UIViewController <UIPopoverControllerDelegate>
3. Inside the method (void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender
if ([segue.identifier isEqualToString:@"NAME_OF_YOUR_SEGUE"]) {
//- for this purpose alone, you don't really need a popSegue property, but having a reference
//- to the popover segue is useful
self.popSegue = (UIStoryboardPopoverSegue *)segue;
//- this gets the reference to the actual UIPopoverController which you need to set the delegate
UIPopoverController *pc = [_popSegue popoverController];
//- setting the delegate to self
//- this is important, otherwise the method under (4) won't be called and your button will remain disabled!
pc.delegate = self;
//- disable the button to prevent creating another popover
[_btnSettings setEnabled:NO];
}
4. Implement the following method in the UIPopoverControllerDelegate protocol,
- (void)popoverControllerDidDismissPopover:(UIPopoverController *)popoverController
{
//- renable the setting button
[_btnSettings setEnabled:YES];
}
As the name suggests, this method gets call whenever the user click outsdie the popover view.
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